Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12

Answer:[tex]y = \frac{1}{3}x-4[/tex]Step-by-step explanation:Step 1:  Solve for y in the first equation[tex]3y - x = -12[/tex][tex]3y - x + x = -12 + x[/tex][tex]\frac{3y}{3} = \frac{x}{3} - \frac{12}{3}[/tex][tex]y = \frac{1}{3}x - 4[/tex]Step 2:  Determine the important aspectsWe know that our line is parallel to the other line that has a slope of 1/3 which means that our slope is also going to be 1/3.  We also know that our line crosses the point (18, 2) which means that we can use the point slope form to determine our equationPoint Slope Form → [tex](y-y_1) = m(x - x_1)[/tex]Step 3:  Plug in the information and solve[tex](y-2) = \frac{1}{3}(x - 18)[/tex][tex]y - 2 = \frac{1}{3}x - 6[/tex][tex]y - 2 + 2 = \frac{1}{3}x - 6 + 2[/tex][tex]y = \frac{1}{3}x-4[/tex]Answer: [tex]y = \frac{1}{3}x-4[/tex]